본문내용
=11200%이다.
5. log[Ca2+] 대 log[OH-]를 그래프로 그리고 Ksp를 구하여라.
Ksp=[Ca2+][OH-]2
logKsp=log[Ca2+][OH-]2
logKsp=log[Ca2+]+2[OH-]
log[Ca2+]=logKsp-2log[OH-]
y =logKsp- x
순수한물 log[ca2+]=log0.0325=-1.488 log[OH-]=log0.065=-1.187
0.1M NaOH log[ca2+]=log0.01=-2 log[OH-]=log0.02=-1.699
0.05M NaOH log[ca2+]=log0.019=-1.721 log[OH-]=log0.038=-1.420
0.025M NaOH log[ca2+]=log0.0255-1.593 log[OH-]=log0.051=-1.292
5. log[Ca2+] 대 log[OH-]를 그래프로 그리고 Ksp를 구하여라.
Ksp=[Ca2+][OH-]2
logKsp=log[Ca2+][OH-]2
logKsp=log[Ca2+]+2[OH-]
log[Ca2+]=logKsp-2log[OH-]
y =logKsp- x
순수한물 log[ca2+]=log0.0325=-1.488 log[OH-]=log0.065=-1.187
0.1M NaOH log[ca2+]=log0.01=-2 log[OH-]=log0.02=-1.699
0.05M NaOH log[ca2+]=log0.019=-1.721 log[OH-]=log0.038=-1.420
0.025M NaOH log[ca2+]=log0.0255-1.593 log[OH-]=log0.051=-1.292
소개글