전자기학 7th 연습문제 풀이

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전자기학 7th 연습문제 풀이에 대한 보고서 자료입니다.

본문내용

1.1. Given the vectors M = −10ax + 4ay − 8az and N = 8ax + 7ay − 2az, find:
a) a unit vector in the direction of −M+ 2N.
−M+ 2N = 10ax − 4ay + 8az + 16ax + 14ay − 4az = (26, 10, 4)
Thus
a =
(26, 10, 4)
|(26, 10, 4)|
= (0.92, 0.36, 0.14)
b) the magnitude of 5ax +N− 3M:
(5, 0, 0) + (8, 7,−2) − (−30, 12,−24) = (43,−5, 22), and |(43,−5, 22)| = 48.6.
c) |M||2N|(M+N):
|(−10, 4,−8)||(16, 14,−4)|(−2, 11,−10) = (13.4)(21.6)(−2, 11,−10)
= (−580.5, 3193,−2902)
1.2. The three vertices of a triangle are located at A(−1, 2, 5), B(−4,−2,−3), and C(1, 3,−2).
a) Find the length of the perimeter of the triangle: Begin with AB = (−3,−4,−8), BC = (5, 5, 1),
and CA = (−2,−1, 7). Then the perimeter will be
= |AB| + |BC| + |CA| = √9 + 16 + 64+ √25 + 25 + 1 + √4 + 1 + 49 = 23.9.

키워드

전자기학,   맥그로힐,   헤이트,   7th,   mcgrawhill,   electromagnetics,   William H. Hayt