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< 3; j++)
{
if (com_val[i] == my_val[j])
{
ball++;
if (i == j)
{
ball--;
strike++;
}
}
}
}
printf(\" %d 번째 도전결과 : %d strike, %d ball!! \\n\", x++, strike, ball);
if (strike == 3)
{
printf(\"Game End! \\n\");
pass_flag = 1;
}
strike = 0; ball = 0;
}
return 0;
}
- 결과 도전 프로그래밍 TH
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x)
{
for (int i = 1; i < 10; i++)
{
printf(\"%d x %d = %d \\n\", x, i, x*i);
}
printf(\"\\n\");
}
int main()
{
int num1, num2;
printf(\"두 개의 정수를 입력하세요 \");
scanf_s(\"%d %d\", &num1, &num2);
if (num1 < num2)
{
for (; num1 <= num2; num1++) gugudan(num1);
}
else if (num2 < num1)
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× 9.8m/s = 9.8×10kgm/s = 9.8×10N
②1g → dyne 으로
1g × 980cm/s = 980gcm/s =980dyne
③1g → poundal 으로
1g = 0.001kg × (0.454) = (454)
1g = (454) × 32.17ft/sec =0.071 poundal
1.2 Foot-pound단위제에서 1slug의 질량이 14.59임을 보여라
sol)영국 단위제
1은 0.454kg
1.3 중력가속도
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L = 1, K = 1 일 때 Q = 5
L = 2, K = 2 일 때 Q = 10
L = 3, K = 3 일 때 Q = 15
수확불변
b. Q = (2L + 2K)
L = 1, K = 1 일 때 Q = 2
L = 2, K = 2 일 때 Q = 2.8
L = 3, K = 3 일 때 Q = 3.5
수확감소
c. Q = 3LK²
L = 1, K = 1 일 때 Q = 3
L = 2, K = 2 일 때 Q = 24
L = 3, K = 3 일 때 Q = 81
수확증
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(2) T(m, n) = 5 + (100 - 2) / (2 × 3) = 16.33
T(1, 1) = 104 사이클이므로,
Sp = 104 / 16.33 = 6.37 연습문제 1장 해답
연습문제 2장 해답
연습문제 3장 해답
연습문제 4장 해답
연습문제 5장 해답
연습문제 6장 해답
연습문제 7장 해답
연습문제 8장 해답
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PROBLEMS
11.5. What is the work required for the separation of air (21-mol-% oxygen and 79-mol-% nitrogen) at 25℃ and 1 bar in a steady-flow process into product streams of the pure oxygen and nitrogen, also at 25℃ and 1 bar, if the thermodynamic efficiency of the process 5% and if T_σ=300K?
T
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Chpapter 1 Introduction
PROBLEMS
1.2. At low pressure there is significant difference between the densities of liquids and of gases. For example, at 1 atm the densest gas know to the author is uranium hexafluoride, which has M=352g/mol; its normal boiling point is 56.2 ℃. Calculate its density
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PROBLEMS
2.12.* An open-ended can 1 ft long is originally full of air at 70℉. The can is now immersed in water, as shown in Fig. 2.23. Assuming that the air stays at 70℉ and behaves as ideal gas, how high will the water rise in the can?
≪ 그 림 ≫
P_water=P_atm+P_(water in can)
P_wa
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PROBLEM
Several problems in this section deal with ideal gas. It may be shown that for an ideal gas the enthalpy and internal energy depend on temperature alone. If an ideal gas has an constant heat capacity (which may be assumed in all the ideal gas problems in this chapter), it is very convenie
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3.12. An ideal gas is flowing in a constant-diameter pipe at at a constant temperature. What is the relation of average velocity to pressure?
The average velocity
V_average=Q/A
V_average=m ̇/ρA
The area of pipe
A=π(d/2)^2
The ideal gas
PV=nRT
n/V=P/RT
m/MV=P/RT
ρ/M
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