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공학수학 (Zill&Cullen) 개정 4판 솔루션입니다.
Chapter 1~20 모두 포함.
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공학수학(zill&cullen) chapter1 ~ chapter20
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1. From y = c1ex +c2e−x we find yꠓ = c1ex −c2e−x. Then y(0) = c1 +c2 = 0, yꠓ(0) = c1 −c2 = 1 so that c1 = 1/2
and c2 = −1/2. The solution is y = 1
2 ex − 1
2 e−x.
2. From y = c1e4x + c2e−x we find yꠓ = 4c1e4x − c2e−
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1. From y = c1ex +c2e−x we find y = c1ex −c2e−x. Then y(0) = c1 +c2 = 0, y(0) = c1 −c2 = 1 so that c1 = 1/2
and c2 = −1/2. The solution is y = 1
2 ex − 1
2 e−x.
2. From y = c1e4x + c2e−x we find y = 4c1e4x − c2e−x. Then y(0) = c1 + c
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