digital_image_processing

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digital_image_processing에 대한 보고서 자료입니다.

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Problem Solution

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2 Problem Solutions
Problem 2.1
The diameter, x, of the retinal image corresponding to the dot is obtained from similar
triangles, as shown in Fig. P2.1. That is,
(d=2)
0:2
=
(x=2)
0:014
which gives x = 0:07d. From the discussion in Section 2.1.1, and taking some liberties
of interpretation, we can think of the fovea as a square sensor array having on the order of
337,000 elements, which translates into an array of size 580£ 580 elements. Assuming
equal spacing between elements, this gives 580 elements and 579 spaces on a line 1.5
mm long. The size of each element and each space is then s = [(1:5mm)=1; 159] =
1:3£10¡6 m. If the size (on the fovea) of the imaged dot is less than the size of a single
resolution element, we assume that the dot will be invisible to the eye. In other words,
the eye will not detect a dot if its diameter, d, is such that 0:07(d) < 1:3 £ 10¡6 m, or
d < 18:6 £ 10¡6 m.
Figure P2.1
Problem 2.4
(a) From the discussion on the electromagnetic spectrum in Section 2.2, the source of
the illumination required to see an object must have wavelength the same size or smaller
than the object. Because interest lies only on the boundary shape and not on other spectral
characteristics of the specimens, a single illumination source in the far ultraviolet
(wavelength of .001 microns or less) will be able to detect all objects. A farultraviolet
camera sensor would be needed to image the specimens. (b) No answer required since
the answer to (a) is af?rmative.

키워드

디지털이미지프로세싱,   솔루션,   digital image processing,   정보통신,   디지털,   problem solution,   solution